In order to find the position of an element on a webpage, Pass the element handle as parameter to the following function on the page. This function works with XPages on Notes Client as well.
function getElementPosition( htmlElement ) {
var xPos = 0;
var yPos = 0;
while( htmlElement && !isNaN( htmlElement.offsetLeft ) && !isNaN( htmlElement.offsetTop ) ) {
xPos += htmlElement.offsetLeft - htmlElement.scrollLeft;
yPos += htmlElement.offsetTop - htmlElement.scrollTop;
htmlElement = htmlElement.parentNode;
}
return { top: yPos, left: xPos };
}
Illustration,
Put the following code on a button which includes the above function and click it.
var myElement=document.getElementById(thisEvent.target.id);
try{
var coorde=getElementPosition( myElement );
var x = coorde.left;
var y = coorde.top;
alert(x+" "+y);
} catch (error) {
alert(error.message);
}
Hope that helps :)
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